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The Refractive Index Of A Lens Material Is 1.5. Lt is now immersed in water $\bigg(\mu = \frac{4}{3}\bigg).$ its new focal length is Explain, giving reasons, whether it will behave as a converging lens or a.
Chapter 26 The Refraction of Light Lenses and Optical from vdocuments.site
Ii) refractive index of medium, nl = 1.33 therefore, fl and fa are of the same sign. If the radii of curvatures are equal, the value of radius of curvature is (in cm) The refractive index of a material is 1.33.
Calculate The Refractive Index Of The Medium.
Given, refractive index of glass, ng = 1.5 therefore, focal length of lens in liquid, a) i) ng = 1.5, nl so fi and fa are of opposite sign. A concave lens of refractive index 1.5 is immersed in a medium of refractive index 1.65. The radii of curvature of the two surfaces are equal i.e.
A Double Convex Lens Made Of A Material Of Refractive Index 1.5 And Having A Focal Length Of 10 Cm Is Immersed In Liquid Of Refractive Index 3.0.
Therefore, convex in liquid 1 behaves as a diverging lens. Lt is now immersed in water $\bigg(\mu = \frac{4}{3}\bigg).$ its new focal length is Ii) refractive index of medium, nl = 1.33 therefore, fl and fa are of the same sign.
The Refractive Index Of Prescription Lenses Extends From 1.5 Standard Index To 1.74 High Index.
Asked oct 6, 2018 in physics by richa ( 60.7k points) The refractive index of the medium is 2. If the focal length is f, applying lens maker formula,
Refractive Index =1.5 And R=20 Cm.
A double concave lens with the refractive index (n) = 1.5 is kept in the air. They are known as cr 39 and have index 1.5. (ii) medium b of refractive index 1.33.
Substituting The Values In The Equation, We Get.
Its two spherical surfaces have radii r 1 = 20 cm and r 2 = 60 cm. N = 3 × 108 m/s/1.5 × 108 m/s = 2. As the refractive index of the medium =1.65 is more than that of a concave lens =1.5 it's nature will change and lens will become a convex lens
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